[R6RS] non-opaque record equality

[Michael Sperber]

William D Clinger <will at ccs.neu.edu> writes:

> Kent wrote:
>>   (equal? (f) (f))      nonterminating if procedures are records,
>>                         #f otherwise
>
> If procedures were records, wouldn't they be *opaque*
> records?

Not necessarily.  Specifically, in system where "opaque" means "can't
inspect in the debugger."

-- 
Cheers =8-} Mike
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