[r6rs-discuss] [Formal] Unclear how equality predicates behave on NaN

From: Michael Sperber <sperber>
Date: Fri Oct 6 09:32:03 2006

William D Clinger <will_at_ccs.neu.edu> writes:

> Per Bothner wrote:
>> 9.10.2 Numerical operations p 39
>> Arithmetic operations
>> = explicitly specifies the behavior for +inf.0 and -inf.0, but not
>> for +nan.0. Implicitly, if any operand is +nan.0, then the result
>> should be #f, and this follows IEEE-754. However, it should be
>> stated explicitly.
>
> There are examples of this in section 16.4, but
> it would be nice to have an example in 9.10.2 also.

Will do for the next revision.

-- 
Cheers =8-} Mike
Friede, V?lkerverst?ndigung und ?berhaupt blabla
Received on Fri Oct 06 2006 - 09:31:54 UTC

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