John Cowan <cowan_at_ccil.org> writes:
> But what's really at stake here is that users shouldn't expect
> reliable results from eqv? on two NaNs generated by different
> processes (where reading "+nan.0" counts as a process), even
> on a single system.
Ok. But currently R6RS doesn't guarantee that (eqv? x x) when x
is NaN, and it should.
--
__("< Marcin Kowalczyk
\__/ qrczak_at_knm.org.pl
^^ http://qrnik.knm.org.pl/~qrczak/
Received on Wed Sep 20 2006 - 10:14:17 UTC