[r6rs-discuss] How about a "fold" procedure?

From: Marcin 'Qrczak' Kowalczyk <qrczak>
Date: Thu Sep 28 20:27:52 2006

"Pinku Surana" <suranap_at_gmail.com> writes:

> It'd be nice to have a simple "fold" procedure which does not impose
> an iteration order when one is not required (like hash-table-fold).
> Most implementators will likely (define fold fold-left).

Is there any implementation which would not?

-- 
   __("<         Marcin Kowalczyk
   \__/       qrczak_at_knm.org.pl
    ^^     http://qrnik.knm.org.pl/~qrczak/

Received on Thu Sep 28 2006 - 20:27:34 UTC