[r6rs-discuss] eqv? seems unwell

From: Mikael Tillenius <mti>
Date: Thu, 28 Jun 2007 09:44:04 +0200

John Cowan escribi?:
> Alan Watson scripsit:
>
>> "Moreover, if (eqv? obj1 obj2) returns #t, then obj1 and obj2 behave the
>> same when passed as arguments to any procedure that can be written as a
>> finite composition of Scheme???s standard procedures."
>
> I think the problem can be removed by adding the words
> "other than eq?" to the end.

And remq, memq etc. Or at least clarify. I would say that remq both is a
standard procedure and can be written as a finite composition of other
standard procdures but maybe I'm missing something.

Also, the above implies that eqv? is equivalent to eq? for pairs,
strings and vectors in the presence of set-car!, string-set! and
vector-set!. Is that intentional?

/Mikael
Received on Thu Jun 28 2007 - 03:44:04 UTC